8k^2+5k-40=-8

Solution for 8k^2+5k-40=-8 equation:

8k^2+5k-40=-8

We move all terms to the left:

8k^2+5k-40-(-8)=0

We add all the numbers together, and all the variables

8k^2+5k-32=0

a = 8; b = 5; c = -32;
Δ = b2-4ac
Δ = 52-4·8·(-32)
Δ = 1049
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$k_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$k_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$k_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(5)-\sqrt{1049}}{2*8}=\frac{-5-\sqrt{1049}}{16}
$
$k_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(5)+\sqrt{1049}}{2*8}=\frac{-5+\sqrt{1049}}{16}
$